Given 28.2 grams of an unknown substance, if the substance absorbs 2165 joules of energy and the temperature increases by 35 Kelvin, what is the specific heat of the substance?
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Specific heat: Q = mcdT.
Q=heat to change temp of substance = 2165J
m=mass of heated substance= 28.2 g
c=specific heat capacity = ?
dT=temp change = 35K
c = 2165/ (28.2)(35)
c = 2.19 x 100 J/g·K
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