(a) An ideal gas occupies a volume of 2.6 cm3 at 20°C and atmospheric pressure.

Physics
Tutor: None Selected Time limit: 1 Day

Jun 23rd, 2015

Thank you for the opportunity to help you with your question! the solution is as such:

Root-mean-square speed is the measure of the speed of particles in a gas that is most convenient for problem solving within the kinetic theory of gases. It is defined as the square root of the average velocity-squared of the molecules in a gas. It is given by the formula

v (r.m.s) = (3kT/ m) ^ 0.5

where k = boltzman constant = 1.38 * 10 ^ - 23 J/K

T is temp in kelvins

and m= mass of a molecule


so for a carbon dioxide molecule to attain escape speed from earth v=  1.12 * 10 ^4 = (3kT/ m) ^ 0.5

so T= [(1.12 * 10 ^ 4 ) ^ 2] * 7.30* 10^ -26  / [3* 1.38* 10^ -23 ]

T= 221186.47 K


for a carbon dioxide molecule to attain escape speed from moon v=  2.37 * 10 ^3 = (3kT/ m) ^ 0.5

so T= [(2.37 * 10 ^ 3 ) ^ 2] * 7.30* 10^ -26  / [3* 1.38* 10^ -23 ]

T= 9904.1 K




Please let me know if you need any clarification. I'm always happy to answer your questions.awaiting a positive feedback. thank you.
Jun 23rd, 2015

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