A space station in the form of a large wheel, 155 m in diameter, rotates to provide an “artificial" gravity” of 3.7 m/s^2 for people located on the outer rim. Find the rotational frequency of the wheel that will produce this effect.
Thank you for the opportunity to help you with your question!
a= 3.7 m/s^2
I then calculated the velocity by a=v^2/r so 3.7=v^2/(155/2) v = sqrt ( 3.7*155/2) = 16.93369 m/sAngular velocity = linear velocity / Circumference = 16.93369 / (pi*155) = 0.034775 rev/sin minutes = 0.034775* 60 = 2.08651 rpm
Content will be erased after question is completed.
Enter the email address associated with your account, and we will email you a link to reset your password.
Forgot your password?