A space station in the form of a large wheel, 155 m in diameter, rotates to provide an “artificial" gravity” of 3.7 m/s^2 for people located on the outer rim. Find the rotational frequency of the wheel that will produce this effect.

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r= 155/2m a= 3.7 m/s^2 I then calculated the velocity by a=v^2/r so 3.7=v^2/(155/2) v = sqrt ( 3.7*155/2) = 16.93369 m/sAngular velocity = linear velocity / Circumference = 16.93369 / (pi*155) = 0.034775 rev/sin minutes = 0.034775* 60 = 2.08651 rpm

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