Physics word problem
Physics

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The tub within a washer goes into its spin cycle, starting from rest and reaching an angular speed of 16π rad/s in 7.2 s. At this point, the lid is opened, and a safety switch turns off the washer. The tub slows to rest in 16.7 s. Through how many revolutions does the tub turn? Assume constant angular acceleration while the machine is starting and stopping. Answer in units of rev
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answering it...5 more mins.....................Figure change in angular acceleration to slow down
α = ω/t
α = 16[pi] rad/s /16.7 s
α = 6.98 r/s^2
Plug into the general equation
θ = ωt  1/2 t^2
θ = 16*pi*7.2  1/2*6.98*7.2^2
θ = 180.99 rad
180.99 /2 pi = 33 revs
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wait the above calculation is not correct
α = ω/t
α = 16[pi] rad/s /16.7 s
α = 3 r/s^2
Plug into the general equation
θ = ωt  1/2 t^2
θ = 16*pi*16.7  1/2*3*16.7^2
θ = 421.098 rad
421.098 /2 pi = 67.02 revs
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