a volume of 40.0 mL of iron (II) sulfate is oxidized to iron (III) by 20.0 mL of 0.100 M potassium dichromate solution
Thank you for the opportunity to help you with your question!
Hi, Kaliyah! Are you wanting to know the concentration of the iron II solution?
Thank you for your reply and yes I am. I repost the question becasuse I saw I didn't include it the first time.
Using principle of equivalence ,Equivalent of FeSO4 = 20*10^-3*0.1*6 =12*10^-3
20= 20 ml iron III , 10^-3 brings you from ml to L, 0.1- M potassiumMass of FeSO4 = 12*10^-3*56 =672*10^-3Conc. = Mass/V(liters) =16.8 M
Thank you so much. This helps out a lot.
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