a volume of 40.0 mL of iron (II) sulfate is oxidized to iron (III) by 20.0 mL of 0.100 M potassium d

Chemistry
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a volume of 40.0 mL of iron (II) sulfate is oxidized to iron (III) by 20.0 mL of 0.100 M potassium dichromate solution

Jun 24th, 2015

Thank you for the opportunity to help you with your question!

Hi, Kaliyah! Are you wanting to know the concentration of the iron II solution?

Please let me know if you need any clarification. I'm always happy to answer your questions.
Jun 24th, 2015

Thank you for your reply and yes I am. I repost the question becasuse I saw I didn't include it the first time.

Jun 24th, 2015

Using principle of equivalence ,

Equivalent of FeSO4 = 20*10^-3*0.1*6 =12*10^-3

20= 20 ml iron III , 10^-3 brings you from ml to L, 0.1- M potassium

Mass of FeSO4 = 12*10^-3*56 =672*10^-3

Conc. = Mass/V(liters) =16.8 M

This should be your answer! Let me know if you have any questions

Jun 24th, 2015

Thank you so much. This helps out a lot.

Jun 24th, 2015

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