##### What is the concentration of the Iron (III) Sulfate Solution?​

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A volume of 40.0 mL of Iron (II) Sulfate is oxidized to Iron (III) by 20.0 mL of 0.100 M Potassium dichromate solution. What is the concentration of the Iron (III) Sulfate Solution?

Jun 24th, 2015

This is a classic chemistry problem that deals with Molarity.

Just use this equation M1V1 = M2V2

M1 is molarity for the potassium dichromate = 0.100M

V1 is the volume of original Iron (II) sulfate before oxidation  = 40.0 mL

V2 is the final volume after the Iron(II) sulfate is oxidized to Iron (III) by 20 ml Potassium dichromate. So the

final volume is 40ml + 20ml = 60 ml

Solve for M2

M2 = M1V1/V2

= (0.100M) ( 40 ml) / 60 ml

= 4 M ml/ 60 ml

= 0.067 M

Jun 24th, 2015

Thank you for your time and this helped tremendiously.

Jun 24th, 2015

Hello, sure and if you have anymore questions. Pls do not hesitate to ask.

Jun 24th, 2015

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Jun 24th, 2015
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Jun 24th, 2015
Dec 6th, 2016
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