find g " (x) for g(x) = x^3lnx

Calculus
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find g " (x) for g(x) = x^3lnx

Jun 24th, 2015

g'(x) = 3x^2 ln(x) + x^3 *1/x 

         = 3x^2 ln(x) +x^2

g''(x) = 3*2*x ln(x) +3x^2 *1/x + 2x

           = 6xln(x) + 3x +2 x

             = 6xln(x) +5x

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Jun 24th, 2015

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Jun 24th, 2015

find g "(x) for g(x) = x^2 ln x

Jun 24th, 2015

Please post this as a separate question

Jun 24th, 2015

why did u post the same question

Jun 24th, 2015

find g " (x) for g(x) = x^3lnx

g'(x) = 3x^2 ln(x) + x^3 *1/x 

         = 3x^2 ln(x) +x^2

g''(x) = 3*2*x ln(x) +3x^2 *1/x + 2x

           = 6xln(x) + 3x +2 x

             = 6xln(x) +5x 

or g''(x) = x (6lnx +5)


Jun 24th, 2015

For f(x)=3x^3-6x^2 find the following 

a.) the intervals where f(x) is increasing and/or decreasing

b.) the local extrema 

c.) the intervals where f(x) is concave up and/or concave down 

d.) the points of inflection 

after finding the information use it to sketch y=f(x) please label answers 

Jun 24th, 2015

Please post this as a separate question..............................

Jun 24th, 2015

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Jun 24th, 2015
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