find g " (x) for g(x) = x^2ln x
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we have : g(x) = x²ln(x)
so : g'(x) = (x²)'ln(x) + (x²)(ln(x))' = 2xln(x) + x²/x = 2xln(x) + x
and : g"(x) = (2xln(x) + x)' = ((2x)'ln(x) + 2x(ln(x))' + x' ) = ( 2ln(x) + 2x(1/x) + 1) = 2ln(x) + 2 + 1 = 2ln(x) + 3
so : g"(x) = 2ln(x) + 3
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