The mass defect for the following reaction, subscript 1 superscript 1 H plus sub

Chemistry
Tutor: None Selected Time limit: 1 Day

The mass defect for the following reaction, , is 0.00239 amu. (1 amu= 1.66X10-27 kg) How much energy will this reaction provide?

Jun 25th, 2015

Thank you for the opportunity to help you with your question!

Since you know the mass defect, use \( E = mc^2\) to find the binding energy per mole. Then find the binding energy per atom, then per nucleon, since there are 16 nucleons per atom of \(^{16}O\

E = (0.00239 amu) *(3 * 10^8)^2

E =(0.00239 * 1.66X10-27 ) * (9 *10^16)

   = 2.39*1.66 *9 * 10^-14

 = 3.571 * 10^-13

so third option is correct

Please let me know if you need any clarification. I'm always happy to answer your questions.
Jun 25th, 2015

Studypool's Notebank makes it easy to buy and sell old notes, study guides, reviews, etc.
Click to visit
The Notebank
...
Jun 25th, 2015
...
Jun 25th, 2015
Dec 4th, 2016
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer