##### In a period of 0.9 s, 5.0 1023 nitrogen molecules strike a wall of area 9.0 cm2

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In a period of 0.9 s, 5.0  1023 nitrogen molecules strike a wall of area 9.0 cm2. If the molecules move at 280 m/s and strike the wall head on in a perfectly elastic collision, find the pressure exerted on the wall. (The mass of one N2 molecule is 4.68  10-26 kg.)

Pa
Jun 26th, 2015

Plastic collision hence  difference of the speed for molecules   ∆v = 280 - (-280) =  560 m/s

The force exerted on the wall :
F =n * ∆p/∆t = n * m∆v/∆t = 5.0 × 10^ (23) * 4.68 × 10^(–26) * 560/0.9 = 14.56 N

therefore pressure exerted on the wall can be,  P = F/A = 14.56 / [9 x 10^(-4)] = 16177.78  N/m^2

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Jun 26th, 2015

thank you for the 10 \$

Jun 26th, 2015

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Jun 26th, 2015
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Jun 26th, 2015
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