In a period of 0.9 s, 5.0 1023 nitrogen molecules strike a wall of area 9.0 cm2. If the molecules move at 280 m/s and strike the wall head on in a perfectly elastic collision, find the pressure exerted on the wall. (The mass of one N2 molecule is 4.68 10-26 kg.)
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Plastic collision hence difference of the speed for molecules ∆v = 280 - (-280) = 560 m/s
The force exerted on the wall :
F =n * ∆p/∆t = n * m∆v/∆t = 5.0 × 10^ (23) * 4.68 × 10^(–26) * 560/0.9 = 14.56 N
therefore pressure exerted on the wall can be, P = F/A = 14.56 / [9 x 10^(-4)] = 16177.78 N/m^2
Answer : 16177.78 Pa
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