An archer must exert a force of 330 N on the bowstring shown in Figure (a) such

Physics
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Jun 26th, 2015

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Jun 26th, 2015

(a). Using cosine rule,  R² = 2F²(1 - cos (180° - 2 * 30°))

330² = 2F²(1 - cos (180° - 2 * 30°))

F =190.5255 N

(b).  F = -k Δx

190.5255 = -k * (-0.34)

k = 560.3693 N/m

Jun 26th, 2015


Jun 26th, 2015
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