##### An archer must exert a force of 385 N on the bowstring shown in Figure (a) such

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Jun 26th, 2015

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Jun 26th, 2015

(a). Using cosine rule,   R² = 2F²(1 - cos (180° - 2 * 30°))

385² = 2F²(1 - cos (180° - 2 * 35°))

F =544.472 N

(b).   F = -k Δx

296450 = -k * (-0.25)

k = 2177.888 N/m

Jun 26th, 2015

wrong

Jun 26th, 2015

wrong

Jun 26th, 2015

(a). Using cosine rule,  R² = 2F²(1 - cos (180° - 2 * 35°))

385² = 2F²(1 - cos (180° - 2 * 35°))

F =234.999 N

(b).  F = -k Δx

234.999 = -k * (-0.25)

k = 939.996 N/m

Jun 26th, 2015

wrong

Jun 26th, 2015

still wrong

Jun 26th, 2015

T = 385 N

K = 1540 N/m

Jun 27th, 2015

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Jun 26th, 2015
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Jun 26th, 2015
May 28th, 2017
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