The free-fall acceleration on Mars is 3.7 m/s2. (a) What length pendulum has a p


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The free-fall acceleration on Mars is 3.7 m/s2.
(a) What length pendulum has a period of 2.0-s on Earth?
 cm

(b) What length pendulum would have a 2.0-s period on Mars?
 cm

An object is suspended from a spring with force constant 10 N/m.
(c) Find the mass suspended from this spring that would result in a 2.0 s period on Earth.
 kg

(d) Find the mass suspended from this spring that would result in a 2.0 s period on Mars.
 kg
Nov 23rd, 2017

Thank you for the opportunity to help you with your question!

a) Use formula for time period of the pendulum: 

T = 2π*sqrt(L/g) 

Make L the subject of formula: 

L = g* (T/2π)^2 

At earth, g=9.8m/s^2; you want T=2 so substituting it in the formula above: 

L = 9.8*(2/2π)^2 = 0.99 m =99cm
For Mars, do the same as above, just put g=3.7 instead of 9.8. 

L = 3.7*(2/2π)^2 = 0.37 m =37cm

b) Use spring formula: 

T = 2π*SQRT(m/k) 

Make m the subject of formula: 

m = k*(T/2π)^2 

For both earth and mars, k=10 so the answer will the same for both planets. 

m = 10 * (2/2π)^2 = 1.01 Kg 


Please let me know if you need any clarification. I'm always happy to answer your questions.
Jun 26th, 2015

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