Description
The free-fall acceleration on Mars is 3.7 m/s2.
(a) What length pendulum has a period of 2.0-s on Earth?
cm
(b) What length pendulum would have a 2.0-s period on Mars?
cm
An object is suspended from a spring with force constant 10 N/m.cm
(b) What length pendulum would have a 2.0-s period on Mars?
cm
(c) Find the mass suspended from this spring that would result in a 2.0 s period on Earth.
kg
(d) Find the mass suspended from this spring that would result in a 2.0 s period on Mars.
kg
kg
(d) Find the mass suspended from this spring that would result in a 2.0 s period on Mars.
kg
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Explanation & Answer
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a) Use formula for time period of the pendulum:
T = 2π*sqrt(L/g)
Make L the subject of formula:
L = g* (T/2π)^2
At earth, g=9.8m/s^2; you want T=2 so substituting it in the formula above:
L = 9.8*(2/2π)^2 = 0.99 m =99cm
For Mars, do the same as above, just put g=3.7 instead of 9.8.
L = 3.7*(2/2π)^2 = 0.37 m =37cm
b) Use spring formula:
T = 2π*SQRT(m/k)
Make m the subject of formula:
m = k*(T/2π)^2
For both earth and mars, k=10 so the answer will the same for both planets.
m = 10 * (2/2π)^2 = 1.01 Kg
Please let me know if you need any clarification. I'm always happy to answer your questions.
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