Given that a linear equation has a slope of –3 and a y-intercept of 1, determine the point-slope form of the line.
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Standard point slope form of a line is -
y = mx + c
m is the slope, and c is the y intercept
Given in the question -
m = -3 and c = 1
therefore, required point slope form is -
y = -3x + 1
That is not one of the answers to choose from
Can you tell me the options?
Yes, y-1=-3x, y+1=-3x, y-3=1x, y+3=-1x
Equation I provided earlier is ..... y = -3x + 1
rearrange above equation and take '1' on left hand side, you will get -
y-1 = -3x
so the answer is first option.
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