An archer must exert a force of 385 N on the bowstring shown in Figure (a) such

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Jun 27th, 2015

Thank you for the opportunity to help you with your question!

1) 2Tsin(30)=385

T=385/2*sin(30)

T=385 N


2)F=kx

385=K*25*10^-3

K=15400 N/m



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Jun 27th, 2015

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