How many moles of Mg3P2 can be produced from the reaction of 0.14 M Mg with 0.020 M P4?
6 Mg + P4 --> 2 Mg3P2
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Here, P4 has less M, so it becomes the deciding factor.
1M of P4 with 6M of Mg gives 2M of Mg3P2.
Here, 0.02M of P4 with 6 x 0.02 M = 0.12M of Mg will give 2 x 0.02M= 0.04M of Mg3P2
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