Need help finding the percentile. How do you caculate the score that marks the 30th percentile under

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Calculate the score that marks the 30th percentile under the normal curve with a mean of 49.15 and a standard deviation of 9.218

Jun 27th, 2015

Thank you for the opportunity to help you with your question!

30 percentile from standard normal distribution is -0.525

thus z = -0.525 = (x-49.15)/9.218 

x = 49.15-0.525*.9218 = 48.666

Please let me know if you need any clarification. I'm always happy to answer your questions.
Jun 27th, 2015

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