A waterfall is 130 m high. What is the increase in water temperature at the bott

Physics
Tutor: None Selected Time limit: 1 Day

  1. A waterfall is 130 m high. What is the increase in water temperature at the bottom of the falls if all the initial potential energy goes into heating the water? (g = 9.8 m/s2cw = 4,186 J/kg⋅°C)
    a.
    b.
    c.
    d.
    e.
Jun 27th, 2015

Thank you for the opportunity to help you with your question! the solution is as such:

The total potential energy = mgh and the increase in internal energy is mc (∆T). So when the complete potential energy is converted into heat energy then, 

m * g* h = m * c * (∆T)

(∆T) = m * g* h/ (m * c )

So here ∆ t = 304.3


Please let me know if you need any clarification. I'm always happy to answer your questions.awaiting a positive feedback. thank you.
Jun 27th, 2015
  1. ∆ t =304.3 / 1000 = 0.3
Jun 27th, 2015

It was nice helping u. Looking forward to help u again. :)

Jun 27th, 2015

Are you studying on the go? Check out our FREE app and post questions on the fly!
Download on the
App Store
...
Jun 27th, 2015
...
Jun 27th, 2015
Dec 4th, 2016
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer