A waterfall is 130 m high. What is the increase in water temperature at the bott

label Physics
account_circle Unassigned
schedule 1 Day
account_balance_wallet $5

  1. A waterfall is 130 m high. What is the increase in water temperature at the bottom of the falls if all the initial potential energy goes into heating the water? (g = 9.8 m/s2cw = 4,186 J/kg⋅°C)
    a.
    b.
    c.
    d.
    e.
Oct 20th, 2017

Thank you for the opportunity to help you with your question! the solution is as such:

The total potential energy = mgh and the increase in internal energy is mc (∆T). So when the complete potential energy is converted into heat energy then, 

m * g* h = m * c * (∆T)

(∆T) = m * g* h/ (m * c )

So here ∆ t = 304.3


Please let me know if you need any clarification. I'm always happy to answer your questions.awaiting a positive feedback. thank you.
Jun 27th, 2015
  1. ∆ t =304.3 / 1000 = 0.3
Jun 27th, 2015

It was nice helping u. Looking forward to help u again. :)

Jun 27th, 2015

Studypool's Notebank makes it easy to buy and sell old notes, study guides, reviews, etc.
Click to visit
The Notebank
...
Oct 20th, 2017
...
Oct 20th, 2017
Oct 21st, 2017
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer