Evaluate the function at the indicated values. (If an answer is undefined, enter

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f(x) = 
x2 + 2x    if x ≤ −1
xif −1 < x ≤ 1
−1if x > 1
f(−4) = 
f
− 
3
2
 = 
f(−1) = 
f(0) = 
f(45) = 

f(x) = 
x2if x < 0
x + 4    if x ≥ 0

f(−2) = 
f(−1) = 
f(0) = 
f(1) = 
f(2) = 

f(x) = 5x2 + 4x − 10

f(
2
)
 = 
 
f(x + 1) = 
 
f(−x) = 
Oct 21st, 2017

Thank you for the opportunity to help you with your question!

Question #1
f
(x) =x2 + 2x

f(-4) =(-4)^2 + 2(-4)= 8

f(x) =x2 + 2x

f(-3/2)= (-3/2)^2 + 2(-3/2) = (9/2) -(6/2)= -3/4

f(x) =x2 + 2x

f(-1) =(-1)2 + 2(-1) = -1

f(x) =x

f(0) = (0)^2=0

f(x) = -1

f(45)= -1

Question#2

f(x) = x^2

f(-2) = (-2)^2 =4

f(-1) = (-1)^2 =1

f(x) = x+4

f(0) = 0+4= 4

f(1) = 1+4=5

f(2) = 2+4=6

Question#3

f(x) = 5x2 + 4x − 10

f(2) = 5(2)2 + 4(2) − 10= 18

f(x+1) = 5(x+1)2 + 4(x+1) − 10= 5(X^2 +1 +2x) + 4x+4-10

=5X^2 +5 +10x + 4x+4-10 = 5x^2 +14x-1

f(-x) = 5(-x)2 + 4(-x) − 10=5x2 -4x − 10

Please let me know if you need any clarification. I'm always happy to answer your questions.
Jun 27th, 2015

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