##### Evaluate the function at the indicated values. (If an answer is undefined, enter

label Algebra
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f(x) =
 x2 + 2x if x ≤ −1 x if −1 < x ≤ 1 −1 if x > 1
f(−4) =
f−
 3 2
=
f(−1) =
f(0) =
f(45) =

f(x) =
 x2 if x < 0 x + 4 if x ≥ 0

 f(−2) = f(−1) = f(0) = f(1) = f(2) =

f(x) = 5x2 + 4x − 10

f(
 2
)
=

f(x + 1) =

f(−x) =
Oct 21st, 2017

Question #1
f
(x) =x2 + 2x

f(-4) =(-4)^2 + 2(-4)= 8

f(x) =x2 + 2x

f(-3/2)= (-3/2)^2 + 2(-3/2) = (9/2) -(6/2)= -3/4

f(x) =x2 + 2x

f(-1) =(-1)2 + 2(-1) = -1

f(x) =x

f(0) = (0)^2=0

f(x) = -1

f(45)= -1

Question#2

f(x) = x^2

f(-2) = (-2)^2 =4

f(-1) = (-1)^2 =1

f(x) = x+4

f(0) = 0+4= 4

f(1) = 1+4=5

f(2) = 2+4=6

Question#3

f(x) = 5x2 + 4x − 10

f(2) = 5(2)2 + 4(2) − 10= 18

f(x+1) = 5(x+1)2 + 4(x+1) − 10= 5(X^2 +1 +2x) + 4x+4-10

=5X^2 +5 +10x + 4x+4-10 = 5x^2 +14x-1

f(-x) = 5(-x)2 + 4(-x) − 10=5x2 -4x − 10

Jun 27th, 2015

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Oct 21st, 2017
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Oct 21st, 2017
Oct 22nd, 2017
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