Consider two steel rods, A and B. B has three times the area and twice the lengt

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  1. Consider two steel rods, A and B. B has three times the area and twice the length of A, so Young's modulus for B will be what factor times Young's modulus for A?
    a.
    b.
    c.
    d.
Jun 28th, 2015

Thank you for the opportunity to help you with your question!

F/A=Y(e/L)

considering B

F/3A=Y(e/2L)

Y=2/3(FL/e)

but for A

Y=(FL/e)


so the factor is

=3/2

=1.5

Please let me know if you need any clarification. I'm always happy to answer your questions.
Jun 28th, 2015

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Jun 28th, 2015
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Jun 28th, 2015
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