A room has a volume of 70 m3 and is filled with air of an average molecular mass

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A room has a volume of 70 m3 and is filled with air of an average molecular mass of 29 u. What is the mass of the air in the room at a pressure of 1.0 atm and temperature of 24°C? R = 0.082 L⋅atm/mol⋅K
a.
b.
c.
d.
e.
Jun 28th, 2015

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Jun 28th, 2015

PV = n R T

therefore n = PV/(RT) = 1*70000/(0.082*297) = 2874.27 moles

mass = 2874*29x10^(-3) = 83.25 kg

Correct Option : D

Jun 28th, 2015

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