If the column of mercury in a barometer stands at 73.6 cm, what is the atmospheric pressure? (The density of mercury is 13.6 × 10^{3} kg/m^{3} and g = 9.80 m/s^{2})

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We know,

Pressure = density X g X height

so, P = (13.6X10^2) * (9.80) * (73.6/100) ...............height is divided by 100 to convert it into meters from cm

P = 98.094 x 10^3

Answer is option d.

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