The filament temperature of a light bulb is 2,050 K when the bulb delivers 40 W

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The filament temperature of a light bulb is 2,050 K when the bulb delivers 40 W of power. If its emissivity remains constant, what power is delivered when the filament temperature is 2,400 K?

a.
b.
c.
d.
e.
Jun 28th, 2015

Thank you for the opportunity to help you with your question!

According to Stefan's law, radiation power is proportional to the 4th power of absolute temperature. 
Then: 
P1 : T1^4 = P2 : T2^4 
P2 = P1 (T2/T1)^4 = 40 x (2400/2050)^4 = 40 x 1.17^4 = 75w
Answer D is the correct one 

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Jun 28th, 2015

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