The filament temperature of a light bulb is 2,050 K when the bulb delivers 40 W

Physics
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The filament temperature of a light bulb is 2,050 K when the bulb delivers 40 W of power. If its emissivity remains constant, what power is delivered when the filament temperature is 2,400 K?

a.
b.
c.
d.
e.
Jun 28th, 2015

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According to Stefan's law, radiation power is proportional to the 4th power of absolute temperature. 
Then: 
P1 : T1^4 = P2 : T2^4 
P2 = P1 (T2/T1)^4 = 40 x (2400/2050)^4 = 40 x 1.17^4 = 75w
Answer D is the correct one 

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Jun 28th, 2015

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