##### I need to work this out

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A wildlife biologist observes four brown bears as they attempt to catch salmon in a river in Alaska.  Assume that each bear has a .7 probability of catching a fish and that the bears fishing attempts are independent.  Let the random variable X be the number of bears that catch a fish.  Create the probability distribution for X (rounding each to THREE decimal places).

What is the mean of the above distribution?
Jun 28th, 2015

Now, given the following probability:

P= 0.7 and q = 0.3

P(X=0)= 4C0*0.3^4= 0. 0081

P(X=1)= 4C1*0.7*0.3^3 = 0. 076

P(X=2)= 4C2*0.7 ^  2 *0.3^2= 0. 2646

P(X=3)= 4C3*0.7^ 3* 0.3^1= 0.4116

P(X=4)= 4C4*0.7^ 4 = 0.2401

Please let me know if you need any clarification. I'm always happy to answer your questions.awaiting a positive feedback. It was lovely helping you. Looking forward to help you again. A positive feedback awaited thank you.
Jun 28th, 2015

The mean is pi × xi

It is 2.8004

Jun 28th, 2015

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Jun 28th, 2015
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Jun 28th, 2015
Dec 8th, 2016
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