I need to work this out

Statistics
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A wildlife biologist observes four brown bears as they attempt to catch salmon in a river in Alaska.  Assume that each bear has a .7 probability of catching a fish and that the bears fishing attempts are independent.  Let the random variable X be the number of bears that catch a fish.  Create the probability distribution for X (rounding each to THREE decimal places).


What is the mean of the above distribution?
Jun 28th, 2015

Thank you for the opportunity to help you with your question! the solution is as such:

Now, given the following probability: 

P= 0.7 and q = 0.3


P(X=0)= 4C0*0.3^4= 0. 0081

P(X=1)= 4C1*0.7*0.3^3 = 0. 076

P(X=2)= 4C2*0.7 ^  2 *0.3^2= 0. 2646

P(X=3)= 4C3*0.7^ 3* 0.3^1= 0.4116

P(X=4)= 4C4*0.7^ 4 = 0.2401



Please let me know if you need any clarification. I'm always happy to answer your questions.awaiting a positive feedback. It was lovely helping you. Looking forward to help you again. A positive feedback awaited thank you.
Jun 28th, 2015

The mean is pi × xi 

It is 2.8004


Jun 28th, 2015

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