Thank you for the opportunity to help you with your question!
first write balanced equation as follows : 2Na + S → Na2 S
45.3g Na & 105g Sulpher than Na2S = m=?
we know that
23g/mol na and 32.07g/mol sulpher gives 78.05 gm moles Na2S (23*2 +32.05 =78.05g/mol
moles Na available= 45.3 g/23 g/mole=1.96mole
1.96 * (1 mole of Na2S) / (2 mole of Na) = 0.98 mole of Na2S
(0.98 mol of Na2S) X 78.05 g/mol here moles get cancelled with each other hence we get
76.48 g of Na2S (Answer)
Please find the solution enclosed here with .. In case of any doubt please feel free to ask… Do not forget to best my answer… If you are having some other problem please feel free to contact me for quick & quality services..