How many moles of ethane (C2H6) would be needed to react with 62.3 grams of oxygen gas?
Unbalanced equation: C2H6 + O2 → CO2 + H2O
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2 C2H6 +7 O2 = 4 CO2 + 6 H2O moles O2 = 62.3 g / 32 g/mol=1.95 the ratio between C2H6 and O2 is 2 : 7 moles of ethae (C2H6) required = 1.95 x 2/7=0.557
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