Thank you for the opportunity to help you with your question!
First balance the equation
CaCl2 + 2 Na3PO4 = 6 NaCl + Ca3(PO4)2 moles CaCl2 = 89.3 g /110.984 g/mol=0.805 the ratio between CaCl2 and Ca3(PO4)2 is 3 : 1 moles Ca3(PO4)2 = 0.805/3 =0.268 mass Ca3(PO4)2 = 0.268 mol x 310.17 g/mol=83.1 g
Please let me know if you need any clarification. I'm always happy to answer your questions.
Jun 30th, 2015
Studypool's Notebank makes it easy to buy and sell old notes, study guides, reviews, etc.