a 5 g quantity of a diprotic acid was dissolved in water and made up to exactly 275 mL. Calculate the molar mass of the acid if 25 mL of this solution required 10.9 mL of 1 M KOH for neutralization. Assume that both protons of the acid were titrated.
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Work out the moles of KOH used (= 10.9 x 1/1000) 1 mole of acid reacts with 2 moles KOH, so work out the number of moles of acid. These moles are in 25 ml of the acid solution so scale up to find the number of moles in 275ml.
This will be the number of moles of acid in 5 g of it
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Jun 30th, 2015
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