Consider the following functions. f(x) = 36 − x2 , g(x) = 1 + x Find (f +

Algebra
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Consider the following functions.

f(x) = 
36 − x2
,   g(x) = 
1 + x
Find 
(f + g)(x)

 

Find the domain of 
(f + g)(x).
 (Enter your answer using interval notation.)
 

Find 
(f − g)(x).

 

Find the domain of 
(f − g)(x).
 (Enter your answer using interval notation.)
 

Find 
(fg)(x).

 

Find the domain of 
(fg)(x).
 (Enter your answer using interval notation.)
 

Find 
f
g
(x).

 

Find the domain of 
f
g
(x).
 (Enter your answer using interval notation.)
 
Jun 30th, 2015

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Jun 30th, 2015

it is the sqrt of 36 

Jun 30th, 2015

the question is not being posted properly

sorry it is the sqrt of 36-x^2

Jun 30th, 2015

f(x) = 36 − x2

g(x) = (1+x)

Find 

(f + g)(x) = − x2 +x + 37     ( Domain is set of all real numbers )

(f - g)(x) = − x2 -x + 35  ( Domain is set of all real numbers )

(f * g)(x) = (36− x2 ) (x+1)  ( Domain is set of all real numbers )

(f / g)(x) = (36 − x2 ) / (x+1)  ( Domain is set of all real numbers  except x = -1)

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in your last Question    which one was correct


Jun 30th, 2015
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f(x) =sqrt ( 36 − x2 )  = Sqrt { (x+6)(x-6)}

g(x) = (1+x)

Find 

(f + g)(x) = sqrt ( 36 − x2 )+ (x+1)   ; 36 − x>=0 hence x^2 <= 36  or x < = +-6   ; or x<6 & x>-6

( Domain is set of all real numbers between  [-6 ,6]

(f - g)(x) = sqrt ( 36 − x2 ) - (x+1)  ( Domain is set of all real numbers between  [-6 ,6]

(f * g)(x) = sqrt ( 36 − x2 ) * (x+1) ( Domain is set of all real numbers between  [-6 ,6]

(f / g)(x) = sqrt (36 − x2 ) / (x+1)  ( Domain is set of all real numbers between  [-6 ,-1) U (-1, 6]

Jun 30th, 2015

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