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√x + √(x -2)

There are two conditions to be satisfied here

1. for √x we need x ≥ 0

2 For √(x -2) we need x ≥ 2

Hence since condition 2 is more restrictive, it satisfies both.

Hence the domain is { x : x x ≥ 2, where x is any Real number}

In interval notation the domain is [2, ∞ )

sorry I have used the wrong thing re attaching

√x + √(2 -x)

2 For √(x -2) we need x ≤ 2

Hence x must lie between 0 and 2 to satisfy both

Hence the domain is { x : 0 ≤ x ≤ 2, where x is any Real number}

In interval notation the domain is [0, 2]

Answer.docx

Any other question I can do for you _Im free just now

Thanks for that explanation!

You're welcome

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