A 59.0-kg ice skater is moving at 3.93 m/s when she grabs the loose end of a rope, the opposite end of which is tied to a pole. She then moves in a circle of radius 0.870 m around the pole.
(a) Determine the magnitude of the force exerted by the horizontal rope on her arms. (b) Compare this force with her weight.
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a. force exerted =Angular momentum=rmv*sinangle;since is horizontal,the angle is 90 degrees
=0.870m*59.0kg*3.93m/s*sin 90=180.34317 N
b. The force is directly proportional to her weight .This because Force is a factor of momentum.
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