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1. the conservation of momentum when the bullet hits the pendulum is calculated.

Time of fall through a height of 0.06m can be found from the formula

h = ut + 0.5 gt^2 [u (initial velocity of bob)= 0], t = sqrt(2gh)

thus t= sqrt(2*9.8*0.06) = 1.0844 seconds

2. conservation of energy when the bullet+pendulum swing to the top is then calculated.

what is the final answer?

The final answer is 0.6187m/s

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