It's an algebra equation.
(b^2/2a divided by b/a^2) x a/3b
sorry it looks a little weird. It's hard to write out on a laptop. Written out the equation is: b squared over two a divided by b over a squared (all of that is in parenthesis) multiplied by a over 3b.
Thank you for the opportunity to help you with your question!
[(b^2/2a) / ( b/a^2)] * (a/3b)
[(b^2/2a) * ( a^2/b)] * (a/3b)
[(b/2) * ( a)] * (a/3b)
[(a*b)/2] * (a/3b)
answer= (a^2)/6dear let me know if you have problem in understanding the solutionand if you have more questions please put them on bids and select my bidi will help you with A+ work in less moneybest of luck :)
I followed until you got: [(a*b)/2] * (a/3b)
Why wouldn't the first part be [a*(b/2)]
[a*(b/2)] this and [(a*b)/2] is same dear as a(b) = a*b is same
Okay. So how did you get from that to the answer?
both b can b cancel out as [(a*b)/2] * (a/3b) = (a^2 *b)/ 6b = (a^2)/6
dear do you have more questions ?
Hi Can u pls go to the home page and add my name under promotion you will get 10$ free.
dONT FORGET "." after my name
Content will be erased after question is completed.
Enter the email address associated with your account, and we will email you a link to reset your password.
Forgot your password?