college algebra equation

Algebra
Tutor: None Selected Time limit: 1 Day

It's an algebra equation.

(b^2/2a divided by b/a^2) x a/3b

sorry it looks a little weird. It's hard to write out on a laptop. Written out the equation is: b squared over two a divided by b over a squared (all of that is in parenthesis) multiplied by a over 3b.

Jun 30th, 2015

Thank you for the opportunity to help you with your question!

[(b^2/2a) / ( b/a^2)] * (a/3b)

[(b^2/2a) * ( a^2/b)] * (a/3b)

[(b/2) * ( a)] * (a/3b)

[(a*b)/2] * (a/3b)

answer=  (a^2)/6

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Jun 30th, 2015

I followed until you got: [(a*b)/2] * (a/3b)

Why wouldn't the first part be [a*(b/2)]

Jun 30th, 2015

 [a*(b/2)] this and [(a*b)/2] is same dear as a(b) = a*b is same

Jun 30th, 2015

Okay. So how did you get from that to the answer?

Jun 30th, 2015

both b can b cancel out as [(a*b)/2] * (a/3b) = (a^2 *b)/ 6b = (a^2)/6

Jun 30th, 2015

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Jun 30th, 2015

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Jun 30th, 2015

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