Thank you for the opportunity to help you with your question!

Thank you for the opportunity to help you with your question!

An artificial satellite circling the Earth completes each orbit in 122 minutes. (The radius of the Earth is 6.38x 10^6 m. The mass of the Earth is 5.98 x10^24 kg.)

Earth mass (m) = 5.98 x10^24 kg

Earth surface radius (r) = 6.38x 10^6 m

r = orbital radius (m) s = altitude above earth surface (m) ,

R = [T²GMe/4π²]^.333 where T is the period in seconds. R = 8.15E6 m

So,

the altitude of the satellite is,

a) H = R - Re = 1.77E6 m

& value of g at the location of this satellite is gravitational acceleration (g) at orbital radius is,

b) g = GMe/R² = 6.005 m/s²

Please let me know if you need any clarification. I'm always happy to answer your questions.Please let me know if you need any clarification. I'm always happy to answer your questions.

Jun 30th, 2015

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