##### Physics: rotational motion

 Physics Tutor: None Selected Time limit: 1 Day

A 0.480-kg pendulum bob passes through the lowest part of its path at a speed of 3.26 m/s.

(a) What is the magnitude of the tension in the pendulum cable at this point if the pendulum is 73.0 cm long? (b) When the pendulum reaches its highest point, what angle does the cable make with the vertical? (Enter your answer to at least one decimal place.)

(c) What is the magnitude of the tension in the pendulum cable when the pendulum reaches its highest point?

Jun 30th, 2015

(a)
T = mg + mv²/r
T = m(g + v²/r)
T = (0.480 kg)[(9.81 m/s²) + (3.26 m/s)²/(0.800 m)]
T = 11.8 N

(b)
(1/2)mv² = mgy
(1/2)v² = gy
(1/2)(3.26 m/s)² = (9.81 m/s²)(y)
y = 0.6244 m

cosθ = (L - y)/L
cosθ = (0.800 - 0.6244 m) / (0.800 m)
θ = 77.3°

(c)
T = mgcosθ
T = (0.470 kg)(9.81 m/s²)cos77.3°
T = 1.01 N

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Jun 30th, 2015

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Jun 30th, 2015
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Jun 30th, 2015
Dec 7th, 2016
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