Find an equation of the tangent line to the graph

label Calculus
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Jul 1st, 2015

Thank you for the opportunity to help you with your question!

the slope is -10/(e^25) (obtained by differentiating)

so by point slope form

y-1/(e^25) = -10/(e^25){x-5}

y= -10/(e^25) + 51/(e^25)

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Jul 1st, 2015

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Jul 1st, 2015

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