Derive an expression for the rate at which the disease was being spread

label Calculus
account_circle Unassigned
schedule 1 Day
account_balance_wallet $5

Jul 1st, 2015

Thank you for the opportunity to help you with your question!

a) it is  N(x=0) = 8000/(200) = 40 

b) the rate is 

dN/dx = 8000*(-1)*(-199*e^(-x))/(1+199e^(-x))^2 = 8000*199e^(-x)/(1+199*e^(-x))^2 >0 

thus N(x) is increases in (0, infinity).   

Please let me know if you need any clarification. I'm always happy to answer your questions.
Jul 1st, 2015

hi can you clarify what the answer to b is 

Jul 1st, 2015

Studypool's Notebank makes it easy to buy and sell old notes, study guides, reviews, etc.
Click to visit
The Notebank
...
Jul 1st, 2015
...
Jul 1st, 2015
Jun 29th, 2017
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer