Derive an expression for the rate at which the disease was being spread

Calculus
Tutor: None Selected Time limit: 1 Day

Jul 1st, 2015

Thank you for the opportunity to help you with your question!

a) it is  N(x=0) = 8000/(200) = 40 

b) the rate is 

dN/dx = 8000*(-1)*(-199*e^(-x))/(1+199e^(-x))^2 = 8000*199e^(-x)/(1+199*e^(-x))^2 >0 

thus N(x) is increases in (0, infinity).   

Please let me know if you need any clarification. I'm always happy to answer your questions.
Jul 1st, 2015

hi can you clarify what the answer to b is 

Jul 1st, 2015

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