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f'(x) = -(x^2-7)^2+2(1-x)(x^2-7)*2x
f'(3) = -4+2*(-2)*2*6 = -4-48 = -52
the tangent line is then
y-(-8) = -52*(x-3)
y+8 = -52x+156
y = -52x+148
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