Find an equation of the tangent line to the graph of the function at the given p

Calculus
Tutor: None Selected Time limit: 1 Day

Jul 1st, 2015

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f'(x) = -(x^2-7)^2+2(1-x)(x^2-7)*2x 

f'(3) = -4+2*(-2)*2*6 = -4-48 = -52 

the tangent line is then 

y-(-8) = -52*(x-3) 

y+8 = -52x+156 

y = -52x+148

Please let me know if you need any clarification. I'm always happy to answer your questions.
Jul 1st, 2015

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