Find an equation of the tangent line to the graph

label Calculus
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schedule 1 Day
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Find an equation of the tangent line to the graph of y = ln(x2) at the point (5, ln(25)).

Jul 3rd, 2015

Thank you for the opportunity to help you with your question!

differentiate=2in(x)  the gradient equation

y=1/2In(x^2}

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Jul 3rd, 2015

HI this answer is coming in as wrong should i look like 1/ (2ln(x^2)) or (1/2)(ln(x^2))

Jul 3rd, 2015

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Jul 3rd, 2015
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Jul 3rd, 2015
Jun 29th, 2017
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