Find an equation of the tangent line to the graph of y = ln(x^{2}) at the point (5, ln(25)).

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Differentiate y w.r.t. x

2/x is the slope of the tangent line at any point on the curve.

At (5, ln(25)), slope is

We can use the point slope form of a line to find the equation of the tangent.

Point slope form of a line is

where m is the slope of the line

and is a point on the line.

Here, m = 0.4 and = (5, ln(25))

So, equation of tangent line is

ANSWER: y = 0.4x + 1.22

Hi this answer is incorrect

could you have made a wrong calculation

Do you submit the answer online? If yes does the question mention any particular way of giving the answer.

I just checked by plotting the graph and it seems to be correct.

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