Physics Need Help Fast

Physics
Tutor: None Selected Time limit: 1 Day

Jul 4th, 2015

Thank you for the opportunity to help you with your question! the solution is as such:

for a spring F= k (xf - xi)

where

F is the force applied.

k is the spring constant

(xf - xi) is the elongation

so when xi= 67.3m and xf = 70.8m

and F = m*g (i.e. weight of jumper)

          = 59.3* 9.8

          = 581.14 N

so k=  F / (xf - xi)

   = 581.14 / 3.5

   k= 166.04 N/m

so the spring constant k = 166.04 N/m



now when k = 166.04 N/m

F= m*g

   = 57.9* 9.8

 F   = 562.52 N

and xi = 67.3 m

then xf= ?

from, F= k (xf - xi)

xf - xi = F/k

          = 562.52 / 166.04

          = 3.387


so xf = xi + 3.387

    xf = 70.68m

so the final elongation is 70.68m

Please let me know if you need any clarification. I'm always happy to answer your questions.awaiting a positive feedback. It was lovely helping you. Looking forward to help you again. A positive feedback awaited thank you.
Jul 4th, 2015

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