Physics Need Help Fast

Tutor: None Selected Time limit: 1 Day

Jul 4th, 2015

Thank you for the opportunity to help you with your question! the solution is as such:

for a spring F= k (xf - xi)


F is the force applied.

k is the spring constant

(xf - xi) is the elongation

so when xi= 67.3m and xf = 70.8m

and F = m*g (i.e. weight of jumper)

          = 59.3* 9.8

          = 581.14 N

so k=  F / (xf - xi)

   = 581.14 / 3.5

   k= 166.04 N/m

so the spring constant k = 166.04 N/m

now when k = 166.04 N/m

F= m*g

   = 57.9* 9.8

 F   = 562.52 N

and xi = 67.3 m

then xf= ?

from, F= k (xf - xi)

xf - xi = F/k

          = 562.52 / 166.04

          = 3.387

so xf = xi + 3.387

    xf = 70.68m

so the final elongation is 70.68m

Please let me know if you need any clarification. I'm always happy to answer your questions.awaiting a positive feedback. It was lovely helping you. Looking forward to help you again. A positive feedback awaited thank you.
Jul 4th, 2015

Did you know? You can earn $20 for every friend you invite to Studypool!
Click here to
Refer a Friend
Jul 4th, 2015
Jul 4th, 2015
Dec 7th, 2016
Mark as Final Answer
Unmark as Final Answer
Final Answer

Secure Information

Content will be erased after question is completed.

Final Answer