Thank you for the opportunity to help you with your question!
Here, L= 3600 inches and A = 0.0625 inches.
We will use the formula
Error in length= L x delta T
Error in Area= A x 2x delta T
Hence, Error in Length= 3600 x 5 x 10^-6 x 130=2.34
Error in Area= 0.0625 x 2 x 5 x 10^-6 x 130=0.000081
Yes, the error depends on the distance being measured.
The error depends on the length but fractional error or percentage error does not depends on length
Thank you SOO MUCH!!! helped a lot
can you help on 2.9 ?
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