find the general term for {5/1, 8/2, 11/6, 14/24, 17/120}

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5 /1 , 5+3/2*1 , 8+3 /3*2*1 , 11+3/4*3*2*1 , 14+3/5*4*3*2*1 , 17+3/6*5*4*3*2*1 ....

numerator follows Arithmetic progression series .. 5,8,11,14,17

first term, a = 5 ,

common difference d = 3 ,

nth formula = a+(n-1)*d = 5 + (n-1)*3 = 5 + 3n - 3 = 3n+2

denominator follows factorial n

general term will be = 3n+2 / factorial(n)

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