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as di s the the midpoint of ac then ad = dc = ac/2
now <bda + bdc = 180 => <bda = <bdc = 90
now we just have to prove AB is equal to BC as all other parameters are equal that is AD=DC , BD is common in both and both triangles are right angles so
AB = √AD^2 +BD^2
BC = √BD^2 + CD^2
and we know that AD = CD so substituting CD in place AD we get AB = √CD^2 + BD^2
so we get
AD = CD
BD is common hence both triangles are identical.
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