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Torque = Inertia x alpha (angular acceleration rad/s^2)
Torque also equals force x radius
First of all lets find the inertia of the wheel.
hoop = mr^2 = 1.79 x 0.319^2 = 0.18215kg-m^2
Now, Torque = 0.18215 x 4.49= 0.8178/radius= force
0.8178 x 0.0446 =36.47N
What force must be applied to attain acc of 4.49 rad/s^2?
117 N x 0.316 m = 36.972 Nm
36.972/ 0.0446 = 828.96 N
Total = 17.33 + 828.96= 846.29 N (answer)
What force is required if the chain shifts to a 5.65 cm diameter sprocket?
the torque is the same and divide by the radius
The answer comes out to be 1390.9 NPlease let me know if you need any clarification. I'm always happy to answer your questions.
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