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The given equation is 8 x^2-16x+1

Here a= 8, b= -16 and c= 1

Using the formula

x= -{b+-(b^2-4ac)}/2a Put the values of a,b and c.

We get x1= 1+1/4 sqrt 14

x2= 1-1/4 sqrt 14

To find the maximum and minimum value, we will use Perfect square method.

Make the coefficient of positive by multiplying it by in case. Maxima / Minima is decided from the sign of 'a'. If 'a' is positive then we have Minima and for 'a'negative we have Maxima.

Step two: Now make the perfect square with the same and coefficient.

Maxima / Minima lies at the point where this squared term is equal to zero.

Hence, =>

This point is a minima if value of coefficient of x^{2} is positive and vice versa. For our function the point x=1 is a .

Please let me know if you need any clarification. I'm always happy to answer your questions.