##### (c) Find its maximum or minimum value. f(x) =

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f(x) = 8x2 − 16x + 1
(a) Express the quadratic function in standard form.
 f(x) =

(c) Find its maximum or minimum value.

f(x) =

Jul 6th, 2015

The given equation is 8 x^2-16x+1

Here a= 8, b= -16 and c= 1

Using the formula

x= -{b+-(b^2-4ac)}/2a Put the values of a,b and c.

We get x1= 1+1/4 sqrt 14

x2= 1-1/4 sqrt 14

To find the maximum and minimum value, we will use Perfect square method.

Make the coefficient of  positive by multiplying it by  in case.
Maxima / Minima is decided from the sign of 'a'.
If 'a' is positive then we have Minima and for 'a'negative we have Maxima.

Step two:
Now make the perfect square with the same  and  coefficient.

Maxima / Minima lies at the point where this squared term is equal to zero.

Hence,
=>

This point is a minima if value of coefficient of x2 is positive and vice versa. For our function the point x=1 is a .

Jul 6th, 2015

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Jul 6th, 2015
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Jul 6th, 2015
Dec 6th, 2016
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