Physics: Merry Go Round Problem

Physics
Tutor: None Selected Time limit: 1 Day

A horizontal 810-N merry-go-round of radius 1.70 m is started from rest by a constant horizontal force of 45 N applied tangentially to the merry-go-round. Find the kinetic energy of the merry-go-round after 4.0 s. 

(Assume it is a solid cylinder. Also assume the force is applied at the outside edge.) 

Jul 6th, 2015

Thank you for the opportunity to help you with your question!

centripetal force =( m* v^2 )/r

F*r = m* v^2

kinetic energy = 1/2 * m*v ^2

kinetic energy = 1/2 *F*r

kinetic energy = 1/2 *45*1.70

kinetic energy = 38.25

after 4 seconds 

kinetic energy = 153 J

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Jul 6th, 2015

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