Physics: Merry Go Round Problem

Physics
Tutor: None Selected Time limit: 1 Day

A horizontal 810-N merry-go-round of radius 1.70 m is started from rest by a constant horizontal force of 45 N applied tangentially to the merry-go-round. Find the kinetic energy of the merry-go-round after 4.0 s. 

(Assume it is a solid cylinder. Also assume the force is applied at the outside edge.) 

Jul 6th, 2015

Thank you for the opportunity to help you with your question!

centripetal force =( m* v^2 )/r

F*r = m* v^2

kinetic energy = 1/2 * m*v ^2

kinetic energy = 1/2 *F*r

kinetic energy = 1/2 *45*1.70

kinetic energy = 38.25

after 4 seconds 

kinetic energy = 153 J

Please let me know if you need any clarification. I'm always happy to answer your questions. please go to your home page . click on promotion who has a heart icon add my name Asim Reh or my referral link https ://www.studypool.com/Asim Reh?aid=Asim Reh in the open window and promote me we both will get 10$ by study pool promote and best me dear :) best of luck
Jul 6th, 2015

Studypool's Notebank makes it easy to buy and sell old notes, study guides, reviews, etc.
Click to visit
The Notebank
...
Jul 6th, 2015
...
Jul 6th, 2015
May 24th, 2017
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer