##### Hardy-Weinberg conditions?

*label*Biology

*account_circle*Unassigned

*schedule*1 Day

*account_balance_wallet*$5

What is the generalized equation which can be used to calculate genotype frequencies in a population which meets Hardy-Weinberg conditions?

Thank you for the opportunity to help you with your question! the solution is as such:

** Hardy-Weinberg
equilibrium equation**

** In
this equation (p² + 2pq + q² = 1),
p is defined as the frequency of the dominant
allele and q as the frequency of the recessive
allele for a trait controlled by a pair of alleles (A and
a). In other
words, p equals all of the alleles in
individuals who are homozygous
dominant (AA) and half of the alleles in people who are
heterozygous (Aa) for this trait
in a population.
In mathematical terms, this is**

**p = AA + ½Aa**

**Likewise, q
equals all of the alleles in individuals who are homozygous recessive (aa)
and the other half of the alleles in people who are heterozygous (Aa).**

**
q = aa + ½Aa**

**Because there are only two alleles
in this case, the frequency of one plus the frequency of the other must equal 100%, which
is to say**

**
p + q =
1**

**Since this is logically true, then the following must also be
correct:**

**
p = 1 - q**

**There were only a few short steps
from this knowledge for Hardy and Weinberg to realize that the chances of all possible
combinations of alleles occurring randomly is**

**
(p + q)² = 1**

**
or more simply**

**
p² + 2pq + q² = 1**

**In this
equation, p² is the predicted frequency of homozygous dominant (AA)
people in a population, 2pq is the
predicted
frequency of heterozygous (Aa) people, and q² is the
predicted frequency of homozygous recessive (aa)
ones. **

References: http://anthro.palomar.edu/synthetic/synth_2.htm

*check_circle*

*check_circle*

*check_circle*

Secure Information

Content will be erased after question is completed.

*check_circle*