If a ball is thrown directly upward with a velocity of 32 ft/s, its height (in f

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If a ball is thrown directly upward with a velocity of 32 ft/s, its height (in feet) after t seconds is given by y = 32t − 16t2. What is the maximum height attained by the ball? (Round your answer to the nearest whole number.)

 ft

Jul 8th, 2015

Thank you for the opportunity to help you with your question!

y = 32t- 16t^2

At maximum height, dy/dt = 0

Or, 32 -32t = 0

Or, t = 32/32 = 1 sec

Hence, maximum y = 32*1-16*1^2 = 16 ft  Ans. 

Please let me know if you need any clarification. I'm always happy to answer your questions.
Jul 8th, 2015

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