If a ball is thrown directly upward with a velocity of 32 ft/s, its height (in f

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Mathematics

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If a ball is thrown directly upward with a velocity of 32 ft/s, its height (in feet) after t seconds is given by y = 32t − 16t2. What is the maximum height attained by the ball? (Round your answer to the nearest whole number.)

 ft

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Explanation & Answer

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y = 32t- 16t^2

At maximum height, dy/dt = 0

Or, 32 -32t = 0

Or, t = 32/32 = 1 sec

Hence, maximum y = 32*1-16*1^2 = 16 ft  Ans. 

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