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dC/dt = 0.06 - 0.0002*2t = 0
Or, t = 0.06/(0.0002*2) = 150
Hence, C will be maximum after 150 days.
Maximum C = 0.06*150-0.0002*150^2 = 4.5mg/L Ans.
Hence, C will be maximum after 150 minutes..
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