mg/L

Thank you for the opportunity to help you with your question!

dC/dt = 0.06 - 0.0002*2t = 0

Or, t = 0.06/(0.0002*2) = 150

Hence, C will be maximum after 150 days.

Maximum C = 0.06*150-0.0002*150^2 = 4.5mg/L Ans.

Hence, C will be maximum after 150 minutes..

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